Chapter 8 Measurement of Time and Motion Class 7 Science Curiosity NCERT Solutions
Chapter 8 Measurement of Time and Motion NCERT Solutions Class 7 Science
Page No. 118
Let us Enhance Our Learning
1. Calculate the speed of a car that travels 150 meters in 10 seconds. Express your answer in km/h.
Answer
Given,
Distance = 150 meters
Time = 10 seconds
Convert meters to kilometers and seconds to hours:
150 meters = 0.15 km
Now calculate speed:
= 0.15 × 360 = 54 km/h
2. A runner completes 400 meters in 50 seconds. Another runner completes the same distance in 45 seconds. Who has a greater speed and by how much?
Answer
Runner 1:
Distance = 400 meters
Time = 50 seconds
Runner 2:
Distance = 400 meters
Time = 45 seconds
Conclusion:
Runner 2 has a greater speed by:
8.89 m/s - 8 m/s = 0.89 m/s
3. A train travels at a speed of 25 m/s and covers a distance of 360 km. How much time does it take?
Answer
Convert 360 km to meters:
360 km = 3,60,000 meters
Now calculate the time,
Convert seconds to hours:
4. A train travels 180 km in 3 hours. Find its speed in:
(i) km/h
(ii) m/s
(iii) What distance will it travel in 4 hours if it maintains the same speed throughout the journey?
Answer
(i) Speed in km/h:
(ii) Speed in m/s:
Convert 180 km to meters:
180 km = 1,80,000 meters
Now calculate speed in m/s:
= 16.67 m/s
(iii) Distance in 4 hours:
Distance = Speed × Time = 60 km/h × 4 hours = 240 km
5. The fastest galloping horse can reach the speed of approximately 18 m/s. How does this compare to the speed of a train moving at 72 km/h?
Answer
Convert the speed of the train to m/s:
= 20 m/s
Comparison:
The horse moves at 18 m/s.
The train moves at 20 m/s.
Conclusion:
The train is faster than the galloping horse by:
20 m/s - 18 m/s = 2 m/s
6. Distinguish between uniform and non-uniform motion using the example of a car moving on a straight highway with no traffic and a car moving in city traffic.
Answer
Uniform motion
When a car moves on a straight highway with no traffic, it maintains a constant speed. This is uniform motion, where the distance covered in equal time intervals is the same.
Non-uniform motion
In city traffic, the car's speed changes due to stops, slowdowns, and accelerations. This is non-uniform motion, where the distance covered in equal intervals of time is not constant.
7. Data for an object covering distances in different intervals of time are given in the following table. If the object is in uniform motion, fill in the gaps in the table.
Answer
Check for uniform motion:
Keeping in mind, this is an uniform motion, the object must cover equal distances in equal time intervals.
Therefore,
8. A car covers 60 km in the first hour, 70 km in the second hour, and 50 km in the third hour. Is the motion uniform? Justify your answer. Find the average speed of the car.
Answer
Since the car covers different distances in each hour (60 km, 70 km, and 50 km), the motion is non-uniform.
To find the average speed:
Total distance = 60 km + 70 km + 50 km = 180 km
Total time = 3 hours
9. Which type of motion is more common in daily life—uniform or non-uniform? Provide three examples from your experience to support your answer.
Answer
Non-uniform motion is more common in daily life.
Examples:
- A car in city traffic: The car's speed changes due to stops and accelerations.
- A bicycle in a park: The rider's speed changes while turning or stopping.
- People walking: Walking speed varies due to obstacles or fatigue.
10. Data for the motion of an object are given in the following table. State whether the speed of the object is uniform or non-uniform. Find the average speed.
Answer
Check the distance travelled in each time interval:
As the distances covered in each interval are not equal, the motion is non-uniform.
Average Speed = Total Distance/Total Time
Total distance = 60 m (final distance)
Total time = 100 s (final time)
11. A vehicle moves along a straight line and covers a distance of 2 km. In the first 500 m, it moves with a speed of 10 m/s and in the next 500 m, it moves with a speed of 5 m/s. With what speed should it move the remaining distance so that the journey is complete in 200 s? What is the average speed of the vehicle for the entire journey
Answer
Given,
Total distance = 2 km = 2000 meters
First part of the journey: Distance = 500 meters, Speed = 10 m/s
Second part of the journey: Distance = 500 meters, Speed = 5 m/s
Total time for the journey = 200 seconds
Calculate the time taken for the first two parts of the journey
1. For the first 500 meters (speed = 10 m/s):
2. For the next 500 meters (speed = 5 m/s):
Calculate the remaining time for the last 1000 meters
The total time allowed is 200 seconds, and the time spent on the first two parts of the journey is:
Time spent = 50 seconds + 100 seconds = 150 seconds
Thus, the time remaining for the last 1000 meters is:
Remaining time = 200 seconds - 150 seconds = 50 seconds
Calculate the required speed for the remaining 1000 meters
Now, we need to cover the remaining 1000 meters in 50 seconds.
The required speed is:
Calculate the average speed for the entire journey
The average speed for the entire journey is given by:
Total distance = 2000 meters, and Total time = 200 seconds.
So,