# Class 12 Maths NCERT Solutions for Chapter 11 Three Dimensional Geometry Exercise 11.1

### Three Dimensional Geometry Exercise 11.1 Solutions

**1. If a line makes angles 90°, 135°, 45° with the x, y and z axes respectively, find its direction cosines.**

**Solution**

Let direction cosines of the line be l, m, and n.

I = cos 90° = 0

m = cos 135° = -1/√2

n = cos 45° = 1/√2

Therefore, the direction cosines of the line are 0, -1/√2 and 1/√2.

**2. Find the direction cosines of a line which makes equal angles with the coordinate axes.**

**Solution**

Let the direction cosines of the line make an angle a with each of the coordinate axes.

∴ I = cos Î±, m = cos Î±, n = cos Î±

l^{2} + m^{2} + n^{2} = 1

⇒ cos^{2} Î± + cos^{2 }Î± + cos^{2} Î± = 1

⇒ 3 cos^{2} Î± = 1

⇒ cos^{2} Î± = 1/3

⇒ cos Î± = ± 1/√3

Thus, the direction cosines of the line, which is equally inclined to the coordinate axes, are ± 1/√3, ± 1/√3, and ± 1/√3.

**3. If a line has the direction ratios −18, 12, −4, then what are its direction cosines?**

**Solution**

If a line has direction ratios of -18, 12 and -4, then its direction cosines are:

i.e., -18/22 , 12/22, -4/22

-9/11, 6/11, -2/11

Thus, the direction cosines are -9/11, 6/11, and -2/11.

**4. Show that the points (2, 3, 4), (-1, -2, 1), (5, 8, 7) are collinear. **

**Solution**

The given points are A (2, 3, 4), B (−1, −2, 1), and C (5, 8, 7).

It is known that the direction ratios of line joining the points, (*x*_{1}, *y*_{1}, *z*_{1}) and (*x*_{2}, *y*_{2}, *z*_{2}), are given by, *x*_{2} − *x*_{1}, *y*_{2} − *y*_{1}, and *z*_{2} − *z*_{1}.

The direction ratios of AB are (-1 −2), (−2 −3), and (1 −4) i.e., −3, −5, and −3.

The direction ratios of BC are (5 −(−1)), (8 −(−2)), and (7 − 1) i.e., 6, 10, and 6.

It can be seen that the direction ratios of BC are −2 times that of AB i.e., they are proportional.

Therefore, AB is parallel to BC. Since point B is common to both AB and BC, points A, B, and C are collinear.

**5. Find the direction cosines of the sides of the triangle whose vertices are (3, 5, −4), (−1, 1, 2) and (−5, −5, −2)**

**Solution**

The vertices of Î” ABC are A(3, 5, -4), B(-1, 1, 2) and C(-5, -5, -2).

The direction ratios of side AB are (−1 − 3), (1 − 5), and (2 − (−4)) i.e., −4, −4, and 6.

Therefore, the direction cosines of AB are

The direction ratios of BC are (−5 −(−1)), (−5 −1), and (−2 −2) i.e., −4, −6, and −4.

Therefore, the direction cosines of BC are

-217, -317, -217The direction ratios of CA are 3−(−5), 5−(−5) and −4−(−2) i.e. 8, 10 and -2.

Therefore the direction cosines of CA are 882 + 102 +(-22), 1082 + 102 + -22, -282 + 102 + (-228242), 10242, -2242442, 542, -142