## Chapter 8 Quadratic Equations R.D. Sharma Solutions for Class 10th Math Exercise 8.9

1. Ashu is x years old while his mother Mrs Veena is x years old. Five years hence Mrs Veena will be three times old as Ashu. Find their present ages.

**Solution**

2. The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the manâ€™s age at the time. Find their present ages.

**Solution**

3. The product of Shikhaâ€™s age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.

**Solution**

4. The product of Ramuâ€™s age (in years) five years ago and his age (in years) nine years later is 15. Determine Ramuâ€™s present age.

**Solution**

5. Is the following situation possible ? If so, determine their present ages. The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in years was 48.

**Solution**

6. A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.

**Solution**

7. he sum of the reciprocals of Rehmanâ€™s ages (in years) 3 years ago and 5 years from now is 1/3. Find his present age .

**Solution**

8. If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than 5 times her actual age . What is her age now ?

**Solution**

9. At present Ashaâ€™s age (in years) is 2 more than the square of her daughter Nishaâ€™s age. When Nisha grows to her motherâ€™s present age, Ashaâ€™s age would be one year less than 10 times the present age of Nisha . Find the present ages of both Asha and Nisha .

**Solution**