Extra Questions for Class 10th: Ch 4 Carbon and its Compounds Science

Extra Questions for Class 10th: Ch 4 Carbon and its Compounds (Science) Important Questions Answer Included

Very Short Answer Questions (VSAQs): 1 Mark

Q1. Write the next  homologous series  compounds of following compounds
C2H4,CH7OH
Answer
C3H6, C4H9OH

Q2. Identify the functional group in following compound. 
Answer
(i) Aldehyde (ii) Ketone

Q3. What is the general mathematical formula for Alkyne?
Answer
CnH(2n-2)

Q4. Name the process by which unsaturated Carbon compounds are converted into Saturated Carbon compounds. 
Answer
Halogenation

Q5. Write chemical equations representing methane Combustion?
Answer
CH4+O2→CO2+H2O+Energy 

Short Answer Questions-I (SAQs-I): 2 Marks

Q1. Give a chemical test to distinguish between butter and cooking oil. 

Answer

Butter and cooking oil can be distinguished by using alkaline KMnO4. Being unsaturated only cooking oil decolourises the pink colour of alkaline KMnO4 where as butter does not, because it is saturated. Bromine water test is also used where brown colour is discharged by the cooking oil.

Q2. Give a chemical test to distinguish between butter and cooking oil.

Answer

Butter and cooking oil can be distinguished by using alkaline KMnO4. Being unsaturated only cooking oil decolourises the pink colour of alkaline KMnO4 whereas butter does not, because it is saturated.

Q3. An organic compound 'X' reacts with sodium metal to form sodium ethoxide and a gas 'Y'. (a) Identify 'X' and 'Y'. (b) What happens when ethanol is heated at 443 K with conc. H2SO4?

Answer


Q4. What is meant by saponification? Give an example. 

Answer

It is the reaction that forms Soap. When an ester reacts with water in presence of a base, a salt of carboxylic acid, and an alcohol are produced. Such a reaction is called saponification.
For example : When ethyl ethanoate is heated with a solution of sodium hydroxide, sodium ethanoate and ethanol are produced.
CH3COOC2H5+NaOH→CH3COONa+C2H5OH

Short Answer Questions-II (SAQs-II): 3 Marks


Q1. Draw the structures of the following compounds and identify the functional group present in them (i) Butanoic acid (ii) Bromopropane (iii) Butyne

Answer

(i) Functional Group is Carboxylic Acid
(ii) Functional Group is Bromine.
(iii) Functional Group is Carbon Carbon triple bond. C≡C
Q2.  What is meant by Isomers ? Draw the structure of two isomers of butane, C4H10. Explain why we cannot have isomers of first three members of alkane series. 

Answer

Isomers are the compounds which have the same molecular formula but different structural formula.
We cannot have isomers of the first three members of the alkane series because of the following laws of isomers: 
The parent chain should have the most number of carbon atoms. 
The branching cannot be done from the first on the last atom carbon atom of the structure.

Q3. What are covalent compounds ? Why are they different from ionic compounds? List their three characteristics properties.

Answer

(a) Covalent compounds are those compounds which are formed by sharing of electrons between two atoms/which contain covalent bonds. 
(b) Covalent compounds are different from ionic compounds because the ionic compounds are formed by the transference of electrons. 
(c) Three characteristics of covalent compounds :
 (i) Generally have low melting and boiling points.
 (ii) Generally insoluble or less soluble in water but soluble in organic solvents. 
(iii)Do not conduct electricity.

Q4. Why homologous series of carbon compounds are so called ? Write chemical formula of two consecutive members of a homologous series and state the part of these compounds that determines their (i) physical properties, and (ii) chemical properties. 

Answer

Carbon compounds are named as homologous series because they are derived from same general formula, having same functional group, similar chemical properties and show gradation in physical properties. Each member differs from successive  member by —CH2 
The two consecutive members of alkane series are  methane (CH4) and ethane (C2H6). 
These members of a homologous series show gradual change in their physical properties with increase in molecular masses. Their molecular masses and functional groups determine their physical and chemical properties, respectively. 

Long Answer Questions (LAQs): 5 Marks

Q1.  What are micelles ? Why does it form when soap is added to water? Will a micelle be formed in other solvents such as ethanol also ? State briefly how the formation of micelles helps to clean the clothes having oily spots. 

Answer

Soap molecules have two ends-at one end is the hydrocarbon chain which is water repellent, whereas at the other end there is the ionic part which is water soluble end. When soap is dissolved in water if forms a group of many molecules, known as micelle. 
These micelles are formed because their hydrocarbon chains come together and the polar ends are projected outwards.
Micelle formation in ethanol will not occur because the hydrocarbon chain end of the soap will dissolve in ethanol. 
Soaps in the form of micelle are able to dean dirty clothes having oily spots, as the oily dirt is collected in the centre of the micelle, which forms an emulsion in water and on rinsing, the water washes away the micelles with dirt attached to them.

Q2. Make the structure of methane by showing sharing of electrons between carbon and hydrogen atoms. How could you convert methane into chloroform by substitution reaction? Explain with the help of chemical reactions.

Answer


Hydrogen atoms can form one covalent bond, while carbon atoms can form four covalent bonds. Four pairs of electrons are shared in a methane molecule (CH4). When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight-a substitution reaction occurs and the organic product is chloromethane. 
CH4 + Cl2→ CH3Cl + HCl
However, the reaction doesn't stop there, and all the hydrogens in the methane can in turn be replaced by Cl.
CH4 + Cl2→ CH3Cl + HCl
CH3Cl + Cl2→ CH2Cl2 + HCl
CH3Cl + Cl2→ CHCl3 + HCl



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